🎯 Functional Equation Templates — f(x+a)/f(-x) Invariances

Essential for AMC12 problems involving unknown functions and their properties.

🎯 Recognition Cues

  • “Find $f(x)$” — Unknown function to be determined
  • $f(x+a)$ — Function with shifted argument
  • $f(-x)$ — Function with negated argument
  • $f(xy) = f(x) + f(y)$ — Logarithmic-like properties
  • $f(x+y) = f(x) + f(y)$ — Additive properties

📚 Template Solutions

Common Functional Equations

TypeEquationSolutionExample
Additive$f(x+y) = f(x) + f(y)$$f(x) = cx$$f(2) = 2c$
Multiplicative$f(xy) = f(x) + f(y)$$f(x) = c\log x$$f(4) = c\log 4$
Exponential$f(x+y) = f(x)f(y)$$f(x) = a^x$$f(3) = a^3$
Power$f(xy) = f(x)f(y)$$f(x) = x^c$$f(4) = 4^c$

Substitution Strategies

PatternSubstitutionPurposeExample
Zero$x = 0$Find $f(0)$$f(x+y) = f(x) + f(y)$ → $f(0) = 0$
Identity$x = y$Find relationships$f(x+y) = f(x) + f(y)$ → $f(2x) = 2f(x)$
Negative$x = -y$Exploit symmetry$f(x+y) = f(x) + f(y)$ → $f(0) = f(x) + f(-x)$
Reciprocal$x = \frac{1}{y}$Find $f(1)$$f(xy) = f(x) + f(y)$ → $f(1) = 0$

🎯 Worked Examples

Example 1: Additive Functional Equation

Problem: Find all functions $f: \mathbb{R} \to \mathbb{R}$ such that $f(x+y) = f(x) + f(y)$ for all $x,y \in \mathbb{R}$.

Solution:

  1. Substitute $x = 0$: $f(y) = f(0) + f(y)$ → $f(0) = 0$
  2. Substitute $x = -y$: $f(0) = f(x) + f(-x)$ → $f(-x) = -f(x)$ (odd function)
  3. Substitute $y = x$: $f(2x) = 2f(x)$
  4. By induction: $f(nx) = nf(x)$ for all integers $n$
  5. For rationals: $f(\frac{p}{q}x) = \frac{p}{q}f(x)$
  6. For reals: $f(x) = cx$ for some constant $c$ (assuming continuity)
  7. Answer: $f(x) = cx$ for some constant $c$

Example 2: Multiplicative Functional Equation

Problem: Find all functions $f: \mathbb{R}^+ \to \mathbb{R}$ such that $f(xy) = f(x) + f(y)$ for all $x,y > 0$.

Solution:

  1. Substitute $x = y = 1$: $f(1) = f(1) + f(1)$ → $f(1) = 0$
  2. Substitute $y = \frac{1}{x}$: $f(1) = f(x) + f(\frac{1}{x})$ → $f(\frac{1}{x}) = -f(x)$
  3. Substitute $y = x$: $f(x^2) = 2f(x)$
  4. For rationals: $f(x^r) = rf(x)$ for rational $r$
  5. For reals: $f(x) = c\log x$ for some constant $c$ (assuming continuity)
  6. Answer: $f(x) = c\log x$ for some constant $c$

Example 3: Exponential Functional Equation

Problem: Find all functions $f: \mathbb{R} \to \mathbb{R}$ such that $f(x+y) = f(x)f(y)$ for all $x,y \in \mathbb{R}$.

Solution:

  1. Substitute $x = y = 0$: $f(0) = f(0)^2$ → $f(0) = 0$ or $f(0) = 1$
  2. If $f(0) = 0$: $f(x) = f(x+0) = f(x)f(0) = 0$ for all $x$ (constant zero function)
  3. If $f(0) = 1$: $f(x) = f(x+0) = f(x)f(0) = f(x)$ (consistent)
  4. Substitute $y = -x$: $f(0) = f(x)f(-x)$ → $f(-x) = \frac{1}{f(x)}$ (assuming $f(x) \neq 0$)
  5. For rationals: $f(nx) = f(x)^n$ for integers $n$
  6. For reals: $f(x) = a^x$ for some constant $a > 0$ (assuming continuity)
  7. Answer: $f(x) = 0$ or $f(x) = a^x$ for some constant $a > 0$

⚠️ Common Pitfalls

Pitfall: Assuming continuity without justification

  • Fix: Only assume continuity if explicitly stated or if it’s reasonable
  • Example: $f(x+y) = f(x) + f(y)$ has discontinuous solutions without continuity

Pitfall: Forgetting to check all cases

  • Fix: Consider all possible values of variables
  • Example: $f(x^2) = f(x)^2$ has different cases for $x = 0, 1, -1$

Pitfall: Incorrect substitution

  • Fix: Be careful with variable replacement
  • Example: In $f(x+y) = f(x) + f(y)$, substituting $x = y$ gives $f(2x) = 2f(x)$, not $f(x^2) = 2f(x)$

🎯 AMC-Style Worked Example

Problem: Find all functions $f: \mathbb{R} \to \mathbb{R}$ such that $f(x+1) = f(x) + 1$ and $f(x^2) = f(x)^2$ for all $x \in \mathbb{R}$.

Solution:

  1. From first equation: $f(x+1) = f(x) + 1$ for all $x$
  2. Substitute $x = 0$: $f(1) = f(0) + 1$
  3. From second equation: $f(x^2) = f(x)^2$ for all $x$
  4. Substitute $x = 0$: $f(0) = f(0)^2$ → $f(0) = 0$ or $f(0) = 1$
  5. If $f(0) = 0$: $f(1) = 1$
  6. If $f(0) = 1$: $f(1) = 2$
  7. Check $f(1) = 1$: $f(1^2) = f(1) = 1$ and $f(1)^2 = 1^2 = 1$ ✓
  8. Check $f(1) = 2$: $f(1^2) = f(1) = 2$ and $f(1)^2 = 2^2 = 4$ ✗
  9. So $f(0) = 0$ and $f(1) = 1$
  10. By first equation: $f(n) = n$ for all integers $n$
  11. By second equation: $f(x^2) = f(x)^2$ for all $x$
  12. For $x = \frac{1}{2}$: $f(\frac{1}{4}) = f(\frac{1}{2})^2$
  13. Answer: $f(x) = x$ for all $x$ (assuming continuity)

Key insight: Functional equations often require multiple substitutions and careful case analysis.

  • Functions — Functional equations involve unknown functions
  • Symmetry — Look for patterns and relationships
  • Substitution — Replace variables with specific values
  • Continuity — Often needed for complete solutions

📝 Practice Checklist

  • Master basic substitution techniques
  • Practice symmetry recognition
  • Learn common functional equation types
  • Practice case analysis
  • Understand continuity requirements
  • Work on speed and accuracy

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