📈 Linear Equations & Inequalities — One-Variable Systems

Fundamental building blocks for more complex algebraic problems.

🎯 Key Ideas

Linear Equations — Equations of the form $ax + b = 0$ where $a \neq 0$. The solution is $x = -\frac{b}{a}$.

Linear Inequalities — Inequalities using $<$, $>$, $\leq$, $\geq$. Solutions are intervals on the number line.

Interval Notation — Compact way to represent solution sets: $(a,b)$ for open intervals, $[a,b]$ for closed intervals.

📊 Essential Concepts

Linear Equations

TypeFormSolutionExample
Standard$ax + b = 0$$x = -\frac{b}{a}$$2x + 3 = 0$ → $x = -\frac{3}{2}$
With fractions$\frac{x}{a} + \frac{b}{c} = 0$$x = -\frac{ab}{c}$$\frac{x}{2} + \frac{1}{3} = 0$ → $x = -\frac{2}{3}$
With parentheses$a(x + b) = c$$x = \frac{c}{a} - b$$3(x + 2) = 9$ → $x = 1$

Linear Inequalities

SymbolMeaningIntervalExample
$<$Less than$(a,b)$$x < 5$ → $(-\infty, 5)$
$\leq$Less than or equal$[a,b]$$x \leq 3$ → $(-\infty, 3]$
$>$Greater than$(a,b)$$x > -2$ → $(-2, \infty)$
$\geq$Greater than or equal$[a,b]$$x \geq 0$ → $[0, \infty)$

🎯 Micro-Examples

Example 1: Solve $3x - 7 = 2x + 1$

  • Subtract $2x$: $x - 7 = 1$
  • Add $7$: $x = 8$
  • Answer: $x = 8$

Example 2: Solve $2(x + 3) = 4x - 2$

  • Distribute: $2x + 6 = 4x - 2$
  • Subtract $2x$: $6 = 2x - 2$
  • Add $2$: $8 = 2x$
  • Divide by $2$: $x = 4$
  • Answer: $x = 4$

Example 3: Solve $3x + 2 < 8$

  • Subtract $2$: $3x < 6$
  • Divide by $3$: $x < 2$
  • Answer: $x \in (-\infty, 2)$

⚠️ Common Traps & Fixes

Trap: Forgetting to flip inequality sign when multiplying/dividing by negative

  • Fix: Always flip the sign when multiplying or dividing by a negative number
  • Example: $-2x > 6$ becomes $x < -3$ (flipped from $>$ to $<$)

Trap: Incorrect interval notation

  • Fix: Remember $(a,b)$ is open, $[a,b]$ is closed
  • Example: $x < 5$ is $(-\infty, 5)$, not $(-\infty, 5]$

Trap: Losing solutions when clearing fractions

  • Fix: Multiply by the LCD of all denominators
  • Example: $\frac{x}{2} + \frac{1}{3} = \frac{x}{6}$ → multiply by $6$: $3x + 2 = x$

🎯 AMC-Style Worked Example

Problem: Find all real values of $x$ such that $2x - 1 \leq 3x + 2 < 5x - 1$.

Solution:

  1. Split compound inequality: $2x - 1 \leq 3x + 2$ and $3x + 2 < 5x - 1$
  2. Solve first inequality: $2x - 1 \leq 3x + 2$
    • Subtract $2x$: $-1 \leq x + 2$
    • Subtract $2$: $-3 \leq x$
  3. Solve second inequality: $3x + 2 < 5x - 1$
    • Subtract $3x$: $2 < 2x - 1$
    • Add $1$: $3 < 2x$
    • Divide by $2$: $\frac{3}{2} < x$
  4. Combine: $-3 \leq x$ and $x > \frac{3}{2}$
  5. Answer: $x \in \left(\frac{3}{2}, \infty\right)$

Key insight: Compound inequalities require solving each part separately, then finding the intersection.

  • Systems of Equations — Linear equations are components of systems
  • Absolute Value — Often involves linear expressions
  • Word Problems — Linear equations model many real-world situations
  • Graphing — Linear equations have straight-line graphs

📝 Practice Checklist

  • Master basic linear equation solving
  • Practice with fractions and parentheses
  • Learn interval notation
  • Practice compound inequalities
  • Understand graphical interpretation
  • Work on speed and accuracy

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