🎯 Systems of Equations — Linear & Nonlinear

Essential for word problems and geometric applications in AMC contests.

🎯 Key Ideas

Linear Systems — Multiple linear equations with multiple variables, solved by substitution or elimination. The number of solutions depends on the relationship between equations.

Nonlinear Systems — Systems involving quadratics, circles, or other curves, often solved by substitution. These frequently appear in geometric problems.

Parameter Analysis — Understanding how the number of solutions depends on parameter values, often using discriminant or geometric intuition.

📊 Solution Methods

Linear Systems (2×2)

MethodWhen to UseExample
SubstitutionOne variable easily isolated$y = 2x + 1$ into $3x + 2y = 7$
EliminationCoefficients are convenientAdd/subtract equations to eliminate variable
GraphingVisual understanding neededFind intersection points

Linear Systems (3×3)

MethodWhen to UseExample
Gaussian EliminationSystematic approachRow operations to triangular form
SubstitutionOne equation is simple$z = 2$ from $z = 2$
Cramer’s RuleDeterminants are easyUse formula for each variable

Nonlinear Systems

MethodWhen to UseExample
SubstitutionOne equation is linear$y = x + 1$ into $x^2 + y^2 = 5$
EliminationBoth equations are similarSubtract to eliminate terms
SymmetryEquations have symmetry$x^2 + y^2 = 1$ and $xy = \frac{1}{2}$

🎯 Micro-Examples

Example 1: Solve $\begin{cases} 2x + y = 7 \ x - y = 2 \end{cases}$

  • Elimination: Add equations: $3x = 9$, so $x = 3$
  • Substitute: $3 - y = 2$, so $y = 1$
  • Answer: $(3, 1)$

Example 2: Solve $\begin{cases} x^2 + y^2 = 25 \ x + y = 7 \end{cases}$

  • Substitution: $y = 7 - x$ from second equation
  • Substitute: $x^2 + (7-x)^2 = 25$
  • Expand: $x^2 + 49 - 14x + x^2 = 25$
  • Simplify: $2x^2 - 14x + 24 = 0$, so $x^2 - 7x + 12 = 0$
  • Factor: $(x-3)(x-4) = 0$, so $x = 3, 4$
  • Answer: $(3, 4)$ and $(4, 3)$

Example 3: Solve $\begin{cases} x + y + z = 6 \ 2x - y + z = 3 \ x + 2y - z = 4 \end{cases}$

  • Elimination: Add first two: $3x + 2z = 9$ (equation A)
  • Elimination: Add first and third: $2x + 3y = 10$ (equation B)
  • Solve: From A: $z = \frac{9-3x}{2}$; from B: $y = \frac{10-2x}{3}$
  • Substitute: $x + \frac{10-2x}{3} + \frac{9-3x}{2} = 6$
  • Solve: $x = 1$, so $y = \frac{8}{3}$, $z = 3$
  • Answer: $(1, \frac{8}{3}, 3)$

⚠️ Common Traps & Fixes

Trap: Forgetting to check all solutions

  • Fix: Always substitute back into original equations
  • Example: $(3, 4)$ and $(4, 3)$ both satisfy $x^2 + y^2 = 25$ and $x + y = 7$

Trap: Dividing by zero in elimination

  • Fix: Check if coefficients are zero before dividing
  • Example: If $x$ coefficient is zero, use different elimination strategy

Trap: Extraneous solutions in nonlinear systems

  • Fix: Squaring both sides can introduce extra solutions
  • Example: $x + y = 7$ and $x^2 + y^2 = 25$ gives $(3,4)$ and $(4,3)$, but $(4,3)$ might not satisfy original if there were restrictions

🎯 AMC-Style Worked Example

Problem: Find all real solutions to the system: $$\begin{cases} x^2 + y^2 = 13 \ xy = 6 \end{cases}$$

Solution:

  1. Strategy: Use substitution since both equations are symmetric
  2. From second equation: $y = \frac{6}{x}$ (assuming $x \neq 0$)
  3. Substitute: $x^2 + \left(\frac{6}{x}\right)^2 = 13$
  4. Simplify: $x^2 + \frac{36}{x^2} = 13$
  5. Multiply by $x^2$: $x^4 + 36 = 13x^2$
  6. Rearrange: $x^4 - 13x^2 + 36 = 0$
  7. Substitute $u = x^2$: $u^2 - 13u + 36 = 0$
  8. Factor: $(u-4)(u-9) = 0$, so $u = 4, 9$
  9. Solve: $x^2 = 4$ gives $x = \pm 2$; $x^2 = 9$ gives $x = \pm 3$
  10. Find $y$: When $x = 2$, $y = 3$; when $x = -2$, $y = -3$; etc.
  11. Answer: $(2, 3)$, $(-2, -3)$, $(3, 2)$, $(-3, -2)$

Key insight: Symmetric systems often have symmetric solutions.

  • Quadratics — Many nonlinear systems involve quadratics
  • Geometry — Systems often represent geometric intersections
  • Word Problems — Systems model real-world situations
  • Parameter Analysis — Systems with parameters require special techniques

📝 Practice Checklist

  • Master 2×2 linear systems
  • Practice 3×3 linear systems (AMC12)
  • Learn nonlinear system techniques
  • Practice geometric applications
  • Understand parameter analysis
  • Work on speed and accuracy

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