🗺️ Grid Paths

Problems involving counting paths on a grid with various constraints and restrictions.

🎯 Recognition Cues

  • Keywords: “path”, “walk”, “grid”, “lattice”, “right and up”, “diagonal”
  • Setup: Moving on a grid from one point to another
  • Constraints: Blocked squares, diagonal moves, specific directions

📋 Solution Template

  1. Identify the path type:

    • Basic lattice path: Only right and up moves
    • Diagonal path: Includes diagonal moves
    • Blocked path: Some squares are off-limits
  2. Apply the appropriate method:

    • Basic lattice: Use $\binom{m+n}{n}$ formula
    • Diagonal: Use modified formula or recursion
    • Blocked: Use inclusion-exclusion or dynamic programming
  3. Check for symmetry:

    • Reflection symmetry
    • Rotation symmetry
    • Diagonal symmetry

💡 Micro-Examples

Basic Lattice Path

  • Problem: How many ways can you walk from (0,0) to (3,2) moving only right and up?
  • Solution: $\binom{3+2}{2} = \binom{5}{2} = 10$ ways

Diagonal Path

  • Problem: How many ways can you walk from (0,0) to (3,2) moving right, up, or diagonally up-right?
  • Solution: Use recursion: $a_{i,j} = a_{i-1,j} + a_{i,j-1} + a_{i-1,j-1}$

Blocked Path

  • Problem: How many ways can you walk from (0,0) to (3,2) avoiding the square (1,1)?
  • Solution: Total paths - Paths through (1,1) = $\binom{5}{2} - \binom{2}{1} \cdot \binom{2}{1} = 10 - 4 = 6$

⚠️ Common Pitfalls & Variants

Pitfall: Forgetting to account for blocked squares

  • Wrong: “Path from (0,0) to (3,2) avoiding (1,1)” = $\binom{5}{2}$
  • Right: Total - Paths through (1,1) = $\binom{5}{2} - \binom{2}{1} \cdot \binom{2}{1}$

Pitfall: Confusing lattice paths with general paths

  • Wrong: “Path from (0,0) to (3,2)” = $3! \cdot 2! = 12$ ways
  • Right: $\binom{5}{2} = 10$ ways (lattice path formula)

Pitfall: Misapplying diagonal path formulas

  • Wrong: “Diagonal path from (0,0) to (3,2)” = $\binom{5}{2}$
  • Right: Use recursion or modified formula for diagonal moves

🏆 AMC-Style Worked Example

Problem: How many ways can you walk from (0,0) to (4,3) moving only right and up, avoiding the squares (1,1) and (2,2)?

Solution:

  • Step 1: Total paths from (0,0) to (4,3): $\binom{7}{3} = 35$
  • Step 2: Paths through (1,1): $\binom{2}{1} \cdot \binom{4}{2} = 2 \cdot 6 = 12$
  • Step 3: Paths through (2,2): $\binom{4}{2} \cdot \binom{2}{1} = 6 \cdot 2 = 12$
  • Step 4: Paths through both (1,1) and (2,2): $\binom{2}{1} \cdot \binom{2}{1} \cdot \binom{2}{1} = 8$
  • Step 5: By inclusion-exclusion: $35 - 12 - 12 + 8 = 19$

Key insight: Use inclusion-exclusion for multiple blocked squares!


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