๐ฏ Triangle Centers
The four classic triangle centers are fundamental to AMC geometry. Each has unique properties and relationships that frequently appear in contest problems.
๐ฏ The Four Centers
Centroid (G)
Definition: Intersection of the three medians Properties:
- Divides each median in ratio 2:1 (closer to vertex)
- Center of mass of the triangle
- Coordinates: Average of vertex coordinates
Key Formula: If $A(x_1,y_1)$, $B(x_2,y_2)$, $C(x_3,y_3)$, then $G = \left(\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}\right)$
Incenter (I)
Definition: Intersection of the three angle bisectors Properties:
- Center of the incircle (inscribed circle)
- Equidistant from all three sides
- Angle bisector theorem: $\frac{BD}{DC} = \frac{AB}{AC}$
Key Formula: Distance from incenter to side $a$: $r = \frac{A}{s}$ where $A$ is area and $s$ is semi-perimeter
Circumcenter (O)
Definition: Intersection of the three perpendicular bisectors Properties:
- Center of the circumcircle (circumscribed circle)
- Equidistant from all three vertices
- In right triangles, circumcenter is midpoint of hypotenuse
Key Formula: Circumradius $R = \frac{abc}{4A}$ where $A$ is area
Orthocenter (H)
Definition: Intersection of the three altitudes Properties:
- In right triangles, orthocenter is the right angle vertex
- In obtuse triangles, orthocenter is outside the triangle
- Reflect orthocenter across sides to get points on circumcircle
๐ The Euler Line
Amazing Fact: In any non-equilateral triangle, the centroid, circumcenter, and orthocenter are collinear!
Euler Line Properties:
- $G$ is between $O$ and $H$
- $GH = 2 \cdot GO$ (centroid divides in ratio 2:1)
- Distance relationships: $OH^2 = 9R^2 - (a^2 + b^2 + c^2)$
๐ Micro-Examples
Centroid Example
In triangle with vertices $(0,0)$, $(6,0)$, $(3,6)$, the centroid is $G = \left(\frac{0+6+3}{3}, \frac{0+0+6}{3}\right) = (3,2)$.
Incenter Example
In triangle with sides 3, 4, 5, the semi-perimeter is $s = 6$, area is $A = 6$, so inradius is $r = \frac{6}{6} = 1$.
Circumcenter Example
In right triangle with legs 3 and 4, the hypotenuse is 5, so circumradius is $R = \frac{5}{2}$ and circumcenter is at midpoint of hypotenuse.
โ ๏ธ Common Traps
Pitfall: Confusing incenter and circumcenter
- Fix: Incenter is inside, circumcenter can be outside in obtuse triangles
Pitfall: Forgetting Euler line relationships
- Fix: Remember $GH = 2 \cdot GO$ and all three are collinear
Pitfall: Wrong centroid formula
- Fix: Centroid is average of coordinates, not sum
๐ฏ AMC-Style Worked Example
Problem: In triangle $ABC$, the centroid is at $(4,5)$ and one vertex is at $(6,8)$. If the other two vertices are $(2,3)$ and $(x,y)$, find $x + y$.
Solution: Using the centroid formula: $G = \left(\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}\right)$
We have: $(4,5) = \left(\frac{6+2+x}{3}, \frac{8+3+y}{3}\right)$
This gives us:
- $4 = \frac{8+x}{3} \Rightarrow 12 = 8+x \Rightarrow x = 4$
- $5 = \frac{11+y}{3} \Rightarrow 15 = 11+y \Rightarrow y = 4$
Therefore, $x + y = 4 + 4 = 8$.
Answer: $x + y = 8$
๐ Related Topics
- Triangles Basics - Fundamental triangle properties
- Special Segments - Medians, altitudes, angle bisectors
- Coordinate Geometry - Using coordinates with centers
- Mass Points - Alternative approach to centroids
๐ก Quick Reference
Center Locations
- Acute triangle: All centers inside
- Right triangle: Orthocenter at right angle, circumcenter at midpoint of hypotenuse
- Obtuse triangle: Orthocenter and circumcenter outside
Distance Relationships
- Centroid: Divides medians 2:1
- Incenter: Distance to side = inradius
- Circumcenter: Distance to vertex = circumradius
- Orthocenter: No simple distance formula
Special Cases
- Equilateral: All four centers coincide
- Isosceles: All centers lie on axis of symmetry
- Right: Orthocenter = right angle vertex
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