π Equations & Inequalities
Mastering equation solving and inequality techniques is crucial for AMC success. This includes absolute value, systems, and advanced inequality methods.
π― Key Ideas
Absolute Value: $|x| = \begin{cases} x & \text{if } x \geq 0 \ -x & \text{if } x < 0 \end{cases}$
Systems: Multiple equations with multiple variables. Common methods: substitution, elimination, graphing.
Inequalities: AM-GM inequality and other techniques for optimization problems.
π Absolute Value Equations
Basic Strategy
- Isolate the absolute value expression
- Split into two cases: positive and negative
- Solve each case separately
- Check solutions in original equation
Example: $|2x - 3| = 7$
- Already isolated: $|2x - 3| = 7$
- Split: $2x - 3 = 7$ or $2x - 3 = -7$
- Solve: $2x = 10$ or $2x = -4$
- Solutions: $x = 5$ or $x = -2$
- Check: $|2(5) - 3| = |7| = 7$ β and $|2(-2) - 3| = |-7| = 7$ β
Pitfall: Extraneous Solutions
Always check solutions! Some may not work in the original equation.
π Systems of Equations
Substitution Method
- Solve one equation for one variable
- Substitute into other equation(s)
- Solve for remaining variable(s)
- Back-substitute to find all variables
Elimination Method
- Multiply equations to get same coefficients
- Add/subtract to eliminate one variable
- Solve for remaining variable(s)
- Back-substitute
Example: Solve $\begin{cases} x + y = 5 \ 2x - y = 1 \end{cases}$
By Elimination:
- Add equations: $(x + y) + (2x - y) = 5 + 1$
- Simplify: $3x = 6$, so $x = 2$
- Substitute: $2 + y = 5$, so $y = 3$
- Solution: $(2, 3)$
βοΈ AM-GM Inequality
Statement: For positive real numbers $a_1, a_2, \ldots, a_n$: $$\frac{a_1 + a_2 + \cdots + a_n}{n} \geq \sqrt[n]{a_1 a_2 \cdots a_n}$$
Equality: Holds when all numbers are equal.
Applications
- Optimization: Find maximum/minimum values
- Proofs: Establish bounds and relationships
- Problem Solving: Recognize when AM-GM applies
Example: Find minimum of $x + \frac{1}{x}$ for $x > 0$
Solution:
- Apply AM-GM to $x$ and $\frac{1}{x}$: $$\frac{x + \frac{1}{x}}{2} \geq \sqrt{x \cdot \frac{1}{x}} = \sqrt{1} = 1$$
- Multiply by 2: $x + \frac{1}{x} \geq 2$
- Equality when $x = \frac{1}{x}$, so $x = 1$
- Minimum value is 2, achieved when $x = 1$
π― AMC-Style Worked Example
Problem: Find all real solutions to $|x^2 - 4| = 3x$.
Solution:
Case 1: $x^2 - 4 \geq 0$ (i.e., $x \leq -2$ or $x \geq 2$)
- Then $|x^2 - 4| = x^2 - 4$
- Equation: $x^2 - 4 = 3x$
- Rearrange: $x^2 - 3x - 4 = 0$
- Factor: $(x-4)(x+1) = 0$
- Solutions: $x = 4$ or $x = -1$
- Check constraints: $x = 4$ works (since $4 \geq 2$), but $x = -1$ doesn’t (since $-1$ is not $\leq -2$ or $\geq 2$)
Case 2: $x^2 - 4 < 0$ (i.e., $-2 < x < 2$)
- Then $|x^2 - 4| = -(x^2 - 4) = 4 - x^2$
- Equation: $4 - x^2 = 3x$
- Rearrange: $x^2 + 3x - 4 = 0$
- Factor: $(x+4)(x-1) = 0$
- Solutions: $x = -4$ or $x = 1$
- Check constraints: $x = 1$ works (since $-2 < 1 < 2$), but $x = -4$ doesn’t (since $-4$ is not in $(-2, 2)$)
Final Answer: $x = 4$ and $x = 1$
π Common Traps & Fixes
Trap: Forgetting to check case constraints
Fix: Always verify that solutions satisfy the original case conditions.
Trap: Extraneous solutions from squaring
Fix: Check all solutions in the original equation.
Trap: Wrong AM-GM application
Fix: Ensure all numbers are positive before applying AM-GM.
Trap: Missing solutions in systems
Fix: Check all possible combinations and don’t assume unique solutions.
π Quick Reference
Absolute Value Properties
- $|a| \geq 0$ (always non-negative)
- $|a| = |-a|$ (symmetric)
- $|ab| = |a||b|$ (multiplicative)
- $|a + b| \leq |a| + |b|$ (triangle inequality)
AM-GM Special Cases
- Two variables: $\frac{a + b}{2} \geq \sqrt{ab}$
- Three variables: $\frac{a + b + c}{3} \geq \sqrt[3]{abc}$
- Equality when all variables are equal
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